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An 5-kg object moves around a circular track of a radius of 18 cm with a constant speed of 6 m/s. Find (a) The magnitude and direction of the acceleration of the object. (b) The net force acting upon the object causing this acceleration.

Answer :

onyebuchinnaji

(a) The magnitude and direction of the acceleration of the object is 200 m/s².

(b) The force acting upon the object causing this acceleration is 1000 N.

The given parameters:

  • Mass of the object, m = 5 kg
  • Radius of the circular path, r = 18 cm = 0.18 m
  • Speed, v = 6 m/s

The magnitude and direction of the acceleration of the object is calculated as follows;

[tex]a_c = \frac{v^2}{r} \\\\a_c = \frac{6^2}{0.18} \\\\a_c = 200 \ m/s^2[/tex]

The force acting upon the object causing this acceleration is calculated as follows;

[tex]F = ma_c\\\\F = 5 \times 200\\\\F = 1000 \ N[/tex]

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