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A worker is being raised in a bucket lift at a constant speed of 3 ft/s. When the worker's arms are 10 ft off the ground, her coworker throws a measuring tape toward her. The measuring tape is thrown from a height of 6 ft with an initial vertical velocity of 15 ft/s. Projectile motion formula: h = -16t2 vt h0 t = time, in seconds, since the measuring tape was thrown h = height, in feet, above the ground Which system models this situation? h = 3t 10 and h = -16t2 15t 6 10t 3 and h = -16t2 6t 15 -16t2 3t 10 and h =-16t2 15t 6 -16t2 10t 3 and h = -16t2 6t 15.

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zaralovey221

Answer:

There for both questions

Step-by-step explanation:

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The  model system for the given projectile motion is

h = -16t^2 + 15t + 6

The correct option is (A)

Projectile motion:

If a object or particle throw obliquely near the earth's surface under constant acceleration then their motion is called projectile motion.

How to calculate projectile motion?

It is assumed that the worker is being hoisted at a constant speed of 3 feet per second in a bucket lift. Her employee throws a measuring tape toward her when her arms are 10 feet off the ground.

h = a + bt

Where an is the worker's initial height from the ground and b is the rate of change in the worker's hand height from the ground.

h = 10 + 3t

The measuring tape is thrown at a vertical velocity of 15 feet per second from a height of 6 feet. Formula for projectile motion

[tex]h = -16t^2+vt+h_0[/tex]

Where v is the initial height and is the velocity. The equation determines the height of the measuring tape.

Therefore

[tex]h = -16t^2+15t+6[/tex]

The correct answer is (A).

Learn more about projectile motion here-

https://brainly.com/question/4378883

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