Step-by-step explanation:
Using Pythagoras Theorem, we can solve the question.
It states that,
Using the equation above,
a) (1)² + (1)² = (Hypotenuse)²
=> 1 + 1 = (Hypotenuse)²
=> 2 = (Hypotenuse)²
=> Hypotenuse =
[tex] \sqrt{2} [/tex]
b) (Base)² + (1)² = (2)²
=> (Base)² + 1 = 4
=> (Base)² = 3
=> Base =
[tex] \sqrt{3} [/tex]
Hope it helps :)