Answer :
The matrix shown represents its elements in rows and columns
The operation performed by the student is R3 -> 2R2 + R3.
How to determine the matrix operation?
The matrix is given as:
[tex]\left[\begin{array}{cccc}-4&1&2&4&0&-1&3&1&3&2&4&5\end{array}\right][/tex]
Multiply the elements on the second row (Row 2) by 2.
So, we have:
2R2 = 0 -2 6 2
Add these elements to the third row (Row 3).
So, we have:
2R2 + R3 = 3 0 10 7
Replace the row 3 by the above elements.
i.e.
R3 -> 2R2 + R3.
So, we have:
[tex]\left[\begin{array}{cccc}-4&1&2&4&0&-1&3&1&3&0&10&7\end{array}\right][/tex]
Hence, the operation performed by the student is R3 -> 2R2 + R3.
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