There are two ways , so the first part reference to method 1 and and second part reference to method 2.
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PART 1 :-
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[tex] \tt In~\triangle ABC: [/tex]
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[tex] \tt \angle A + \angle B + \angle C = 180 {}^{ \circ} [/tex]
{sum of triangle}
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here we can find value of angle C.
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[tex] \dashrightarrow \sf\angle A + \angle B + \angle C = 180 {}^{ \circ} \\ [/tex]
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[tex] \dashrightarrow \sf112 + 48 + \angle C = 180 {}^{ \circ} \\ [/tex]
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[tex] \dashrightarrow \sf160 + \angle C = 180 {}^{ \circ} \\ [/tex]
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[tex] \dashrightarrow \sf\angle C = 180 {}^{ \circ} - 160 {}^{ \circ} \\ [/tex]
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[tex] \dashrightarrow \sf\angle C =20^{ \circ} \\ [/tex]
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angle c is congruent to angle f
.°. y = 20°
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PART 2:-
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angle a = angle d
.°. value of x = 112°
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[tex] \tt \angle E + \angle D + \angle F = 180 {}^{ \circ} [/tex]
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ve can find value of y :-
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[tex] \dashrightarrow \sf x + 48 + y= 180 {}^{ \circ} \\ [/tex]
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[tex] \dashrightarrow \sf112 + 48 +y = 180 {}^{ \circ} \\ [/tex]
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[tex] \dashrightarrow \sf160+y= 180 {}^{ \circ} \\ [/tex]
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[tex] \dashrightarrow \sf y= 180 {}^{ \circ} - 160 {}^{ \circ} \\ [/tex]
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[tex] \dashrightarrow \bf y=20^{ \circ} \\ [/tex]
