Answer:
[tex]\huge\boxed{\sf 49.41\ L}[/tex]
Explanation:
In the reaction:
for every 3 moles of H₂, 2 moles of NH₃ are produced.
Converting 25 g of Ammonia into moles:
Moles = mass / molar mass
= 25 / (14 + 1 × 3)
= 25 / (14 + 3)
= 25 / 17
= 1.47 mol
From the reaction:
2 NH₃ = 3 H₂
1 NH₃ = 3/2 H₂
1 NH₃ = 1.5 H₂
1.47 mol of NH₃ = 1.5 × 1.47 mol of H₂
1.47 mol of NH₃ = 2.2 mol of H₂
So, 2.2 mol of H₂ are needed to produce 1.47 mol (25 g) of NH₃
Converting 2.2 mol of H₂ into L:
= mole × molar value
[molar value = 22.4 L/mol]
= 2.2 × 22.4
= 49.41 L
[tex]\rule[224]{225}{2}[/tex]
