kcgriffin2005
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A helicopter was hovering over a shelter and was 800 ft above the ground. A medic was on the ground and was looking up at an angle of 65° to the helicopter. The medic’s eyes were 5.5 feet off the ground when looking at this angle of elevation. How far was the medic from the shelter?

Answer :

Using the slope concept, it is found that the medic was 370.5 ft from the shelter.

What is a slope?

The slope is given by the vertical change divided by the horizontal change, and it's also the tangent of the angle of depression.

In this problem:

  • The vertical change is of 800 - 5.5 = 794.5 ft.
  • The horizontal chnge is the distance d.
  • The angle is of 65º.

Hence:

[tex]\tan{65^\circ} = \frac{794.5]{d}[/tex]

[tex]d = \frac{794.5}{\tan{65^\circ}}[/tex]

[tex]d = 370.5[/tex]

The medic was 370.5 ft from the shelter.

More can be learned about the slope concept at https://brainly.com/question/18090623

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