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An m = 7.25 kg mass is suspended on a string which is pulled upward by a force of F = 76.7 N as shown in the figure. If the upward velocity of the mass is 2.25 m/s right now, then what is the velocity 3.50 s later?

An m = 7.25 kg mass is suspended on a string which is pulled upward by a force of F = 76.7 N as shown in the figure. If the upward velocity of the mass is 2.25 class=

Answer :

The velocity after 30s would be 38. 99 m/s

How to calculate the velocity

Using the formula

F = m Δ V/ t

Where, F = force = 76. 7N

m = mass = 7. 25kg

Δv = change in velocity= V2 - V1 and V1 = 2. 25 m/s

t = time = 3. 50s

76. 7 = 7. 25 × (v2 - 2. 25) / 3. 50

76. 7 = 2. 07 × (v2 - 2. 25)

make v2 subject of formula

v2 - 2. 25 = 76. 07 ÷ 2. 07

v2 = 36. 74 + 2. 25

v2 = 38. 99 m/s

Thus, the velocity after 3. 50s would be 38. 99 m/s

Learn more about change in velocity here:

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