Answer :
The stiffness constant of the spring is 68,290.3 N/m
Stiffness constant of the spring
Apply the principle of conservation of energy;
U = K.E
¹/₂kx² = ¹/₂mv²
kx² = mv²
k = mv²/x²
where;
- m is mass
- v is speed = 60 km/h = 16.67 m/s
- x is the distance
k = (1300 x 16.67²)/(2.3²)
k = 68,290.3 N/m
Thus, the stiffness constant of the spring is 68,290.3 N/m.
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