Answer :
The product formed by the an elimination reaction between 2-bromopropane and hot potassium ethoxide, CH₃—CH₂—OK (KBr and ethanol are also products) is trans-2-pentene.
What is an Addition reaction ?
Addition reaction are those in which unsaturated molecules combines with each other to form saturated compound.
Now, This addition reaction takes place according to Markovnikov's rule.
According to this rule, negative part of reactant attacks to that carbon atom which has less number of hydrogen atom.
And the positive part of reactant attacks to that carbon atom which has more number of carbon atom. According to the given reaction H₂O breaks down into H⁺ and OH⁻.
Since, 3-hexene is a symmetrical structure. So, OH⁻ attacks on whichever part the product formed will be same.
Equation:
CH₃CH₂CH=CHCH₂CH₃+ H₂O (H⁺ Catalyst) → CH₃CH₂CHOH-CH₂CH₂CH₃
3-hexene hexan-3-ol
What happens when alkyl halide react with alcoholic KOH ?
When alkyl halide react with alcoholic KOH which supports Elimination Reaction.
The product of this reaction is either cis-2-pentene or trans-2-pentene
But, trans-2-pentene is more symmetrical than cis-2-pentene.
Hence, the major product of this reaction is trans-2-pentene along with KBr and ethanol .
Equation:
CH₃CHBrCH₂-CH₂CH₃ + C₂H₅⁻- OK⁺ → CH₃CH=CHCH₂CH₃ +KBr+C₂H₅OH
2-Bromopentane trans-2-Pentene
Thus from the above conclusion we can say that,the product formed by the an elimination reaction between 2-bromopropane and hot potassium ethoxide, CH₃—CH₂—OK (KBr and ethanol are also products) is trans-2-pentene.
Learn more about Elimination Reaction here:https://brainly.com/question/17101814
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Disclaimer : The question given was incomplete on portal, Here is the complete question.
Question : Write equations for the following:
(a) an addition reaction between H₂O and 3-hexene (H⁺ is a catalyst)
b) an elimination reaction between 2-bromopropane and hot potassium ethoxide, CH₃—CH₂—OK (KBr and ethanol are also products);