Answer :
1. The horizontal component of the velocity is 14.74 m/s
2. The vertical component of the velocity is 10.32 m/s
Data obtained from the question
The following data were obtained from the question:
- Initial velocity (u) = 18 m/s
- Angle of projection (θ) = 35 °
- Horizontal component of velocity =?
- Vertical component of velocity =?
1. How to determine the horizontal component of velocity
- Initial velocity (u) = 18 m/s
- Angle of projection (θ) = 35 °
- Horizontal component of velocity =?
Horizontal component of velocity = u × Cosθ
Horizontal component of velocity = 18 × Cos35
Horizontal component of velocity = 14.74 m/s
2. How to determine the vertical component of velocity
- Initial velocity (u) = 18 m/s
- Angle of projection (θ) = 35 °
- Vertical component of velocity =?
Vertical component of velocity = u × Sineθ
Vertical component of velocity = 18 × Sine35
Vertical component of velocity = 10.32 m/s
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