Answer :
using law of divisibility of 9 and 11
(3+x+0+1+y+6+7+5)÷9 must give a whole number
(22+x+y)÷9
also3+0+y+7=x+1+6+5
x=6 y=8
(3+x+0+1+y+6+7+5)÷9 must give a whole number
(22+x+y)÷9
also3+0+y+7=x+1+6+5
x=6 y=8