Answer :
The percent of pizzas that are less than 12.04 inches is 56.36%
Given the following:
Mean, μ=12
Standard deviation, σ=0.25
Percent of pizzas less than 12.04:
Let P(X<12.04) be percent of pizzas less than 12.04
P(X<12.04)=P(Z<(x-μ)/σ)
=P(Z<(12.04-12)/0.25)
=P(Z<0.16)
Z-value of 0.16 from cumulative standardized normal distribution is 0.5636
Given that P(X<12.04)=P(Z<0.16), and P(Z<0.16) from normal distribution table is 0.5636,
P(X<12.04)=P(Z<0.16)=0.5636
P(X<12.04)=0.5636
=56.36%
Hence, the correct choice is 56.36%
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