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In the equation Q = 45e1.031a quantity Q is changing over time t.(a) What is the quantity at timet = 0?(b) Is the quantity increasing or decreasing over time?(c) What is the percent per unit time continuous growth or decay rate?

Answer :

(a) The equation is given as Q=45e^1.03t

where e=2.718

Taking t=0 the equation will be :

[tex]Q=45e^{1.03\ast0}[/tex]

This will give;

[tex]Q=45\ast2.718^0[/tex]

Q=45

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