Answer :

For the given question, we will use the formula from part (b) to answer part (d)

The given function is as follows:

[tex]S=260.4914\cdot A^{0.2051}[/tex]

We will find the number of species (S) When A = 813

so, substitute with A = 813, then find S

[tex]S=260.4914\cdot813^{0.2051}\approx1029.563[/tex]

Rounding the answer to the nearest 10 species

So, the answer will be:

[tex]S=1030[/tex]

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