Answer :
we have (-3/4b^2)(-6a^2b^5)
so
[tex]\frac{-3b^2}{4}\cdot-6a^2b^5=(-\frac{3}{4}\cdot-6)\cdot a^2b^7=\frac{18}{4}\cdot a^2b^7[/tex]simplify
[tex]\frac{9}{2}a^2b^7[/tex]
we have (-3/4b^2)(-6a^2b^5)
so
[tex]\frac{-3b^2}{4}\cdot-6a^2b^5=(-\frac{3}{4}\cdot-6)\cdot a^2b^7=\frac{18}{4}\cdot a^2b^7[/tex]simplify
[tex]\frac{9}{2}a^2b^7[/tex]