B
Explanation
Step 1
graph the given point and draw a rigth triangle
so , the answer is B
Step 2
when you graph the angle, you get a rigth triangle:
Let
adjancent side=6
opposite side=8
hypotenuse=
[tex]\begin{gathered} hypotenuse^2=6^2+8^2 \\ hypotenuse^2=36+64 \\ hypotenuse^2=100 \\ \text{hypotenuse}=10 \end{gathered}[/tex]now, use those values to find the functions
[tex]\begin{gathered} \sin \emptyset=\frac{opposite\text{ side}}{\text{hypotenuse}}=\frac{8}{10}=\frac{4}{5} \\ \cos \emptyset=\frac{adjacent\text{ side}}{\text{hypotenuse}}=\frac{6}{10}=\frac{3}{5} \\ \tan \theta=\frac{opposite\text{ side}}{\text{adjancent side}}=\frac{8}{6}=\frac{4}{3} \\ \csc \theta=\frac{hyp}{op\text{ si}}=\frac{10}{8}=\frac{5}{4} \\ \sec \theta=\frac{hypo}{\text{adjancent side}}=\frac{10}{6}=\frac{5}{3} \\ \cot \theta=\frac{adjacent\text{ side}}{\text{opposite side}}=\frac{6}{8}=\frac{3}{4} \\ \csc \theta=\frac{hypt}{\text{oppside}}=\frac{10}{8}=\frac{5}{4} \end{gathered}[/tex]I hope this helps you
