Answer :
Okay, here we have this:
Considering the provided information, we are going to calculate the requested time and difference, so we obtain the following:
Question 1:
Considering that the total time is equal to the sum of all the times, we obtain that:
[tex]\begin{gathered} 3\text{ }\frac{3}{10}+2\text{ }\frac{4}{5}+x+2\frac{1}{10}=11\frac{3}{5} \\ \frac{33}{10}+\frac{14}{5}+x+\frac{21}{10}=\frac{58}{5} \\ x+\frac{14}{5}+\frac{33}{10}+\frac{21}{10}=\frac{58}{5} \\ x+\frac{14}{5}+\frac{27}{5}=\frac{58}{5} \\ x+\frac{41}{5}=\frac{58}{5} \\ x=\frac{17}{5} \\ x=3\text{ }\frac{2}{5}\text{ minutes} \end{gathered}[/tex]Finally we obtain that Cindy's time was 3 2/5 minutes.
Question 2:
To calculate the difference between the fastest and the slowest then we will subtract the times of the fast and the slow, so we subtract Nicolle's time from Cindy's:
[tex]\begin{gathered} \text{Difference}=3\text{ }\frac{2}{5}-2\text{ }\frac{1}{10} \\ =1+\frac{3}{10} \\ =1\frac{3}{10} \end{gathered}[/tex]Finally we obtain that the difference is 1 3/10.