Answer :
The question is what rational number for x would make
[tex]\frac{3x+15}{6-x}\text{ = 0}[/tex]We have
[tex]\begin{gathered} \frac{3x+15}{6-x}=0 \\ \text{the numerator must be zero, for this to be zero., so} \\ 3x+15=0 \\ 3x=-15 \\ x=\frac{-15}{3}=-5 \end{gathered}[/tex]So, x = -5 would make the expression zero.
Option B