Answer :
1. A
2.
[tex]\begin{gathered} x^2-9^2=(x-9)(x+9) \\ x^2-7^2=(x-7)(x+7) \\ 4x^2-3^2=(4x-3)(4x+3) \end{gathered}[/tex]difference of squares problem can be factored as follows: a2 – b2 = (a + b)(a – b) or (a – b)(a + b). So, all you need to do to factor these types of problems is to determine what numbers squares will produce the desired results.
3.
[tex](x-5)(x+5)=x^2-5^2[/tex]4.
[tex](x+1)^2=x^2+2x+1[/tex]they are different case of multiplication because the first one is a factoring case and this one is newton's binomial