We can find the equation of a linear equation using the following formula
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1) \end{gathered}[/tex]where
(x1 , y1) = (-3 , 1)
(x2 , y2) = (0 , 0)
Replacing
[tex]y-1=\frac{0-1}{0+3}\cdot(x+3)[/tex]Simplify
[tex]\begin{gathered} y-1=\frac{-1}{3}\cdot(x+3) \\ y-1=-\frac{1}{3}x-\frac{1}{3}\cdot3 \\ y-1=-\frac{1}{3}x-1 \\ y=-\frac{1}{3}x-1+1 \\ y=-\frac{1}{3}x \end{gathered}[/tex]Therefore,
the answer is option A