Answer :
FORMULAS
If A and B are any events then:
[tex]P\mleft(AorB\mright)=P\mleft(A\mright)+P\mleft(B\mright)-P\mleft(AandB\mright)[/tex]If A and B are mutually exclusive events then P(A and B) = 0, so then:
[tex]P\mleft(A\text{ }or\text{ }B\mright)=P\mleft(A\mright)+P\mleft(B\mright)[/tex]The probability of an event happening is given to be:
[tex]P=\frac{\text{Number of required events}}{Number\text{ of total events}}[/tex]SOLUTION STEPS
The total number of pets in the store is calculated to be:
[tex]Total=8+10+6=24[/tex]The probability of picking a puppy is:
[tex]P(p)=\frac{8}{24}[/tex]The probability of picking a kitten is:
[tex]P(k)=\frac{10}{24}[/tex]Therefore, the probability of choosing a puppy or a kitten is gotten to be:
[tex]P(p\text{ }or\text{ }k)=\frac{8}{24}+\frac{10}{24}=\frac{18}{24}=\frac{3}{4}[/tex]ANSWER
The probability is 3/4 or 0.75.