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Linear Equations: Real World ApplicationsA student has scores of 76, 76.5, and 82.75 on his first three tests. He needs an average of at least80 to earn a grade of B. What is the minimum score that the student needs on the fourth test toensure a B? Round your answer to two decimal places.The student needs a minimum score ofon the fourth test to ensure a grade of atleast a B.

Answer :

Let

x ------> score on the fourth test

we have that

[tex]\frac{76+76.5+82.75+x}{4}\ge80[/tex]

Remember that

at least, means -----> "greater than or equal to"

so

solve for x

[tex]76+76.5+82.75+x\ge80\cdot4[/tex]

[tex]235.25+x\ge80\cdot4[/tex]

[tex]\begin{gathered} x\ge320-235.25 \\ x\ge84.75 \end{gathered}[/tex]

therefore

The minimum score on the fourth test is 84.75

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