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Statements: Segment Addition PostulateSubtraction Property of EqualityDefinition of segments (2nd use)Definition of segments (1st use)Substitution Property (2nd use)Symmetric PropertySubstitution Property (1st use) (Place statements to the right —->)

Statements: Segment Addition PostulateSubtraction Property of EqualityDefinition of segments (2nd use)Definition of segments (1st use)Substitution Property (2nd class=

Answer :

Given:

two-Proof are given and it should be named.

[tex]\bar{1.VZ}\approx\bar{VY}\text{ and }\bar{\text{WY}}\approx\bar{XZ}[/tex]

Above proof is by Definition of segments.

[tex]2.VZ=VY\text{ and WY}=XZ[/tex]

Above proof is by Definition of segments.

[tex]3.\text{ }VZ=VX+XZ\text{ and VY=}VW+WY[/tex]

Above proof is by Segment of Addition Postulate.

[tex]4.VX=XZ=VW+WY[/tex]

Above equation is wrong actually it is VX+XZ=VW+WY

and it is by Addition Property of Equality

[tex]5.VX+WY=VW+WY[/tex]

Above equation is by Substitution Property (2nd use)

[tex]6.VX=VW[/tex]

Above equation is by Substitution Property.

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