For the following set of data, find the population standard deviation, to the nearestthousandth.Data Frequency658593163184208521

For the following set of data, find the population standard deviation, to the nearestthousandth.Data Frequency658593163184208521 class=

Answer :

step 1

find out the mean

Mean=[6*5+8*5+9*3+16*3+18*4+20*8+21*5]/(5+5+3+3+4+8+5)

Mean=[30+40+27+48+72+160+105]/33

Mean=482/33

Mean=14.606

step 2

For each value of the data set, subtract the mean and squared the result, then multiply by the frequency

so

[(6-14.606)^2]*5 =370.31618

[(8-14.606)^2]*5=218.19618

[(9-14.606)^2]*3=94.28171

[(16-14.606)^2]*3=5.829708

[(18-14.606)^2]*4=46.076944

[(20-14.606)^2]*8=232.761888

[(21-14.606)^2]*5=204.41618

step 3

Adds the values in step 2

S=1,171.87879

step 3

Divide the sum by the sun of the frequency values

S/33

1,171.87879/33

To obtain the standard deviation, find out the square root

√(1,171.87879/33)

=5.959

therefore

The standard deviation is 5.959

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