The rhombus has four congruent sides and 2 perpendicular diagonals
We can find the area of the rhombus using two methods:
1) if we have the side length and the height of the rhombus
Area = base * height
2) if we have the length of the diagonals
Area = 0.5 * the product of the diagonals
For the given rhombus:
As shown: we have the length of half the diagonals
So, the length of the diagonals will be :
[tex]\begin{gathered} d_1=2\cdot6=12 \\ d_2=2\cdot8=16 \end{gathered}[/tex]So, area =
[tex]\text{Area}=\frac{1}{2}\cdot12\cdot16=\frac{1}{2}\cdot192=96\operatorname{cm}^2^{}[/tex]So, the answer is : area of the rohmbus = 96 square cm.
