Answer :
Each probability lies between 0 to 1, If a customer purchases 2 stoves, the probability is 0.1379 they will also purchase two refrigerators, the average number of refrigerators purchased is 0.93, and the variance in the number of refrigerators purchased is 0.6051.
A) 0 1 2 stoves
0 0.08 0.14 0.12 0.34
1 0.09 0.17 0.13 0.39
2 0.05 0.18 0.04 0.27
RF 0.22 0.49 0.29 1
B) Each probability lies between 0 to 1
All the probabilities sum up to 1
C) P(2 Ref/ 2 stoves) = P(2 Ref and 2 stoves) / 2 stoves)
= 0.04/0.29 = 4/29 = 0.1379
D) Average number of Ref purchased E(x) = ∑xi pi
X 0 1 2
Prob. 0.34 0.39 0.27
= 0.39 + 0.54
= 0.93
E) Var(x) = ∈(x)² - (∈{x})²
= (0.39 + 1.08) - (0.93 * 0.93)
= 1.47 - 0.8649
= 0.6051
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