Answer :
The volume of water and alcohol present in 635 mL of this solution are 381 mL and 254 mL respectively.
As we are given that 40.0 % (v/v) alcohol solution. That means, 40.0 mL of alcohol present 100 mL of solution.
Now we have to calculable the volume of alcohol in 635 mL solution.
As, 100 mL of solution contains 40.0 mL of alcohol
So, 675 mL of solution contains (635/100)*40 = 254 of alcohol
Thus, the volume of alcohol = 254 mL
Now we have to calculate the volume of water.
Volume of water = Volume of solution - Volume of alcohol
Volume of water = 635 mL - 254 mL
Volume of water = 381 mL
Thus, the volume of water = 381 mL
Therefore, the volume of water and alcohol present in 635 mL of this solution are 381 mL and 254 mL respectively.
To learn more about solution, refer: https://brainly.com/question/7932885
#SPJ4