Answer :
I don't know Ioput, but :
gravity is:
[tex]F_g = \frac{mMG}{ R^{2} } [/tex]
simplified to near surface force:
[tex]F_g = mg[/tex]
so :
[tex]g = \frac{MG}{ R^{2} } [/tex]
M mass of planet
R radius of planet
G gravitational constant
gravity is:
[tex]F_g = \frac{mMG}{ R^{2} } [/tex]
simplified to near surface force:
[tex]F_g = mg[/tex]
so :
[tex]g = \frac{MG}{ R^{2} } [/tex]
M mass of planet
R radius of planet
G gravitational constant
The acceleration due to gravity on the surface of the planet Loput is [tex]\boxed{1.93g}[/tex] .
Further Explanation:
Given:
The mass of the Earth is [tex]{M_e}[/tex] .
The radius of the Earth is [tex]{R_e}[/tex] .
The acceleration due to gravity on Earth is [tex]g[/tex] .
The mass of the planet Loput is [tex]5.6{M_e}[/tex] .
The radius of the planet Loput is [tex]1.7{R_e}[/tex] .
Concept:
In the given question, it is considered that Loput is a planet that has the mass and radius more than that of the Earth.
The value of acceleration due to gravity on the surface of any planet is expressed as:
[tex]\boxed{{g_p}=\frac{{G{M_p}}}{{R_p^2}}}[/tex]
Here, [tex]{g_p}[/tex] is the acceleration due to gravity on the planet, [tex]G[/tex] is the gravitational constant, [tex]{M_p}[/tex] is the mass of the planet and [tex]{R_p}[/tex] is the radius of the planet.
The value of acceleration due to gravity on the surface of the Earth is:
[tex]g=\frac{{G{M_e}}}{{R_e^2}}[/tex]
Now for the planet Loput, the value of acceleration due to gravity can be determined as:
[tex]\begin{aligned}{g_L}&=\frac{{G\times\left({5.6{M_e}}\right)}}{{{{\left({1.7{R_e}}\right)}^2}}}\\&=\frac{{5.6}}{{{{\left({1.7}\right)}^2}}}\frac{{G{M_e}}}{{{R_e}}}\\\end{aligned}[/tex]
Substitute [tex]g[/tex] for [tex]\frac{{G{M_e}}}{{{R_e}}}[/tex] in above expression.
[tex]\boxed{{g_L}=1.93g}[/tex]
Thus, the acceleration due to gravity on the surface of the planet Loput is [tex]\boxed{1.93g}[/tex] .
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Answer Details:
Grade: High School
Subject: Physics
Chapter: Gravitation
Keywords:
Acceleration due to gravity, gravity on Loput, mass of planet Loput, 5.6Me, radius of planet Loput, 1.7Re, g=GM/R^2.