Answer :
The solutions to the equation [tex]x^2-16=0[/tex] are x = -4, x = 4
Solutions to quadratic equations
The given quadratic equation is:
[tex]x^2-16=0[/tex]
This can be re-written as:
[tex]x^2-4^2=0[/tex]
Simplifying the equation by applying the difference of two squares
[tex](x-4)(x+4)=0[/tex]
Equate each of the factors to zero
x - 4 = 0
x = 4
x + 4 = 0
x = -4
The solutions to the equation [tex]x^2-16=0[/tex] are x = -4, x = 4
Learn more on quadratic equation here: https://brainly.com/question/1214333