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a batter hits a baseball upward with an initial speed of 96 feet per second. after how many seconds does the ball het the ground

Answer :

Aliwohaish12
h = rt - 16t² = t(r - 16t)

Here, r = 96 so

h = 96t - 16t² = 16t(6 - t)

h = 0 ⇒ 16t(6 - t) = 0 ⇒ t = 0 or t = 6

The t = 0 solution corresponds to the instant the batter hits the ball. It hits the ground 6 seconds later.

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