Answer :

bcalle
I would first cut off the ends that make a trapezoid and then find the area of the trapezoids and the area of the rectangles.
A trap = (1/2) * h *(b1 + b2)
A rect = L * W
A trap = (1/2) 4 * (6 + 14)
A = (1/2) * 4 * 20
A = 40 (there are 2 trapezoids) 40 * 2 = 80 yds^2
A rect = L * W
A = 12 * 4
A = 48 (there are 2 rectangles) 48 * 2 = 96 yds^2
80 + 96 = 176 yds^2
akposevictor

Amount of cement needed = Area of the two trapezoids + Area of the two rectangles = 176 yd².

What is the Area of a Trapezoid?

Area of trapezoid= 1/2(a + b)h

What is the Area of a Rectangle?

Area of a rectangle = (l)(w)

The walkway can be decomposed into two identical trapezoids and two identical rectangles.

Area of the two trapezoids = 2(1/2(a + b)h) = 2(1/2(12 + 20)4) = 128 yd²

Area of the two rectangles = 2[(l)(w)] = 2[(6)(4)] = 48 yd²

The number of square yards of cement needed to create the walkway = 128 + 48 = 176 yd².

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