Answer :
On the ramp the input force is the component of the weight down the ramp =m*g sinc(e)
But sinc(e)=4/20=1/5 so F =1/5*m*g and the distance pushed is 20m
Now for the pulley the 4 segments are of the same rope
So the weight m*g=4*T
So the input force = 1/4 *m*g and the distance moved is 4*4m=16m
But sinc(e)=4/20=1/5 so F =1/5*m*g and the distance pushed is 20m
Now for the pulley the 4 segments are of the same rope
So the weight m*g=4*T
So the input force = 1/4 *m*g and the distance moved is 4*4m=16m