BobbieWasabi
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In the parallelogram shown, AE = p − 8, CE = 2p − 58, and DE = p + 15. What is the length of line segment EB?


42 units
50 units
65 units
73 units

In the parallelogram shown, AE = p − 8, CE = 2p − 58, and DE = p + 15. What is the length of line segment EB? 42 units 50 units 65 units 73 units class=

Answer :

helperjoe
DE = EB

DE = p + 15

I would help you farther but I don't know what p equals. If you know then add that number with 15 and you have your answer.
carlosego

The first thing we must do is find the value of p.

For this, we use the following equality:

[tex] AE = EC
[/tex]

Substituting values we have:

[tex] p - 8 = 2p - 58
[/tex]

Clearing the value of p we have:

[tex] 2p - p = 58 - 8

p = 50
[/tex]

Then, we look for the length of EB.

We know that:

[tex] EB = DE
[/tex]

Substituting values we have:

[tex] EB = p + 15

EB = 50 + 15

EB = 65
[/tex]

Answer:

the length of line segment EB is:

65 units

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