Answer :

[tex]\bf \sqrt{7x}(\sqrt{x}-7\sqrt{7})\implies \sqrt{7x\cdot x}-7\sqrt{7x\cdot 7}\implies \sqrt{7x^2}-7\sqrt{7^2x} \\\\\\ x\sqrt{7}-7\cdot 7\sqrt{x}\implies x\sqrt{7}-49\sqrt{x}[/tex]

Other Questions