Answer :
[tex]|\Omega|=52[/tex]
There are 26 red cards and four 2's. But two 2's are red, so [tex]|A|=26+4-2=28[/tex]
[tex]P(A)=\dfrac{28}{52}=\dfrac{7}{13}\approx54\%[/tex]
There are 26 red cards and four 2's. But two 2's are red, so [tex]|A|=26+4-2=28[/tex]
[tex]P(A)=\dfrac{28}{52}=\dfrac{7}{13}\approx54\%[/tex]