Answer :
The correct answer is b), or x² = -12y.
Explanation:
This equation may be written in standard form as
[tex]y=- \frac{1}{12} x^{2} [/tex]
The coefficient in front of x² is negative so the curve is downward.
The vertex has coordinates (0,0).
The vertex is equidistant from the directrix and the focus, so the focus is (0, -3).
Explanation:
This equation may be written in standard form as
[tex]y=- \frac{1}{12} x^{2} [/tex]
The coefficient in front of x² is negative so the curve is downward.
The vertex has coordinates (0,0).
The vertex is equidistant from the directrix and the focus, so the focus is (0, -3).
