The length of a hollow pipe is 476 cm. The air column in the pipe is vibrating and has
nine nodes. Find the frequency of the sound wave in the pipe. The speed of sound in air is 343 m/s. Answer in units of Hz.

The length of a hollow pipe is 476 cm. The air column in the pipe is vibrating and has nine nodes. Find the frequency of the sound wave in the pipe. The speed o class=

Answer :

Answer: 161.44 Hz

Explanation:

To find the frequency of the sound wave in the pipe, we can use the formula:

Frequency = (v / λ) * n

where:

- v is the speed of sound in air (343 m/s),

- λ (lambda) is the wavelength of the sound wave, and

- n is the number of nodes (9 nodes in this case).

First, we need to find the wavelength of the sound wave. Since the pipe has 9 nodes, there are 10 segments of the wave within the pipe. The pipe is a closed-closed pipe, so the length of the pipe is equal to a quarter of the wavelength (λ/4).

Given the length of the pipe is 476 cm (or 4.76 m), we can calculate the wavelength:

Wavelength (λ) = 4 * Length of the Pipe = 4 * 4.76 = 19.04 m

Now, we can calculate the frequency using the formula:

Frequency = (343 / 19.04) * 9 ≈ 161.44 Hz

Therefore, the frequency of the sound wave in the pipe is approximately 161.44 Hz.

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