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There are three urns containing black, red, and green balls. urn 1 contains 4 black, 5 red, and3 green balls. urn 2 contains 7 black, 4 red, and 4 green balls. urn 3 contains 6 black, 6 red, and 5green balls. a urn is chosen and a ball is picked. if the ball picked is green find the probability it hascome from urn 3.

Answer :

alphabetsam
This is a conditional probability problem. This uses the formula:
[tex]p(B | A)= \frac{p(A and B)}{p(B)}[/tex]

In this case:
[tex]p(B | A)= \frac{p(urn 3 and green)}{p(green)}[/tex]
[tex]p(B | A)= \frac{5/17)}{(12/44)}[/tex]

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