Answer:
B. 0.28 s
Explanation:
From the graph, we can calculate the spring constant of the spring, which is equal to the slope of the force-displacement graph. Taking two random points on the graph, we find:
[tex]k=\frac{\Delta F}{\Delta x}=\frac{2.00 N -1.00 N}{0.08 m-0.04 m}=25 N/m[/tex]
The period of oscillations is given by:
[tex]T=2\pi \sqrt{\frac{m}{k}}[/tex]
where m=50.0 g=0.05 kg is the mass on the spring. Substituting numbers, we find
[tex]T=2\pi \sqrt{\frac{0.05 kg}{25 N/m}}=0.28 s[/tex]
