Answer :
Part 1:
The length of a side is 9 cm.
The square root of 81 is 9. We have to find the square root bc we know it is a square.
Part 2:
The hypotenuse (or diagonal) is c.
Using the Pythagorean Theorem
[tex]a^{2} + {b}^{2} = {c}^{2} [/tex]
you would know that 9 is a and b.
[tex] {9}^{2} + {9}^{2} = {c}^{2} [/tex]
We know that
[tex] {9}^{2} = 81[/tex]
so you add 81 to 81.
[tex]81 + 81 = 162[/tex]
81 and 81 make 162.
So you know ...
[tex]{c}^{2} = 162[/tex]
You take the square root of 162.
[tex] \sqrt{162} = 12.73[/tex]
well almost.
You can write your answer as
[tex]about \: 12.73 cm[/tex]
or
[tex] \sqrt{162} cm[/tex]
Hope I helped!
The length of a side is 9 cm.
The square root of 81 is 9. We have to find the square root bc we know it is a square.
Part 2:
The hypotenuse (or diagonal) is c.
Using the Pythagorean Theorem
[tex]a^{2} + {b}^{2} = {c}^{2} [/tex]
you would know that 9 is a and b.
[tex] {9}^{2} + {9}^{2} = {c}^{2} [/tex]
We know that
[tex] {9}^{2} = 81[/tex]
so you add 81 to 81.
[tex]81 + 81 = 162[/tex]
81 and 81 make 162.
So you know ...
[tex]{c}^{2} = 162[/tex]
You take the square root of 162.
[tex] \sqrt{162} = 12.73[/tex]
well almost.
You can write your answer as
[tex]about \: 12.73 cm[/tex]
or
[tex] \sqrt{162} cm[/tex]
Hope I helped!