Answer :
Answer:
21 cubic inches is the volume of a box that will hold exactly 567 of these cubes with 1/3 inch sides.
Step-by-step explanation:
Given: number of cubes(n) = 567 and sides of cubes = [tex]\frac{1}{3}[/tex] inch.
Volume of cubes states it is found by multiplying the length of any edge by itself twice i,e
Volume of cubes(V) = [tex]a^3[/tex] where a is the sides of the cubes.
then;
Volume of each cubes = [tex](\frac{1}{3})^3 = \frac{1}{27}[/tex] cubic inches.
Since, the box that will hold exactly 567 of these cubes.
⇒Volume of box = n [tex]\times[/tex] volume of each cubes.
Substitute the given values we get;
Volume of a box = [tex]567 \times \frac{1}{27} = 21[/tex] cubic inches.
Therefore, volume of a box that will hold exactly 567 of these cubes with 1/3 inch sides is, 21 cubic inches.