Answer :
when the solution is pure water so,
Kw = [OH-][H3O+]
when [OH-] = [H3O+] we can assume both = X
and Kw = 1.47 x 10^-14
by substitution:
1.47 x 10^-14 = X^2
∴ X = √(1.47 x 10^-14)
= 1.2 x 10^-7 M
Kw = [OH-][H3O+]
when [OH-] = [H3O+] we can assume both = X
and Kw = 1.47 x 10^-14
by substitution:
1.47 x 10^-14 = X^2
∴ X = √(1.47 x 10^-14)
= 1.2 x 10^-7 M