Answer: Sodium chloride's solubility has changed the least from [tex]0^0C-100^0C[/tex] and potassium nitrate's solubility has changed the most from [tex]0^0C-100^0C[/tex].
Explanation:
Solubility in a particular liquid is the amount of solute that can dissolve in unit volume of the liquid to form the saturated solution at the given temperature and under a pressure of 1 atmosphere.
a) Solubility of Potassium iodide at [tex]0^0C[/tex]: 129g/100 ml
Solubility of Potassium iodide at [tex]100^0C[/tex]: 250g/10ml
Change in solubility of Potassium iodide = [tex](250-129)^0C=121^0C[/tex]
b) Solubility of sodium nitrate at [tex]0^0C[/tex]: 70g/100 ml
Solubility of sodium nitrate at [tex]100^0C[/tex]: 180 g/100 ml
Change in solubility of sodium nitrate = [tex](180-70)^0C=110^0C[/tex]
c) Solubility of Potassium nitrate at [tex]0^0C[/tex]: 12g/100 ml
Solubility of Potassium nitrate at [tex]100^0C[/tex]: 235g/100 ml
Change in solubility of Potassium nitrate = [tex](235-12)^0C=223^0C[/tex]
d) Solubility of sodium chloride at [tex]0^0C[/tex]: 36g/100 ml
Solubility of sodium chloride at [tex]100^0C[/tex]: 40 g/100 ml
Change in solubility of sodium chloride= [tex](40-36)^0C=4^0C[/tex]
e) Solubility of Potassium chlorate at [tex]0^0C[/tex]: 5g/100 ml
Solubility of Potassium chlorate at [tex]100^0C[/tex]: 60 g/100 ml
Change in solubility of Potassium chlorate = [tex](60-5)^0C=55^0C[/tex]
Thus we can see that sodium chloride's solubility has changed the least from [tex]0^0C-100^0C[/tex] and potassium nitrate's solubility has changed the most from [tex]0^0C-100^0C[/tex].
