Answer :
Heya user
We have
[tex] \: base \: area \: = \: \pi \: {r}^{2} \: \\ \\ 16\pi = \: \pi \: {r}^{2} \: \: \\ \\ r \: = 4 \: unit \: [/tex]
Now
Surface area = 2πr^2 + 2πrh
→ 2× 16π + 2π × 4× 10
→ 32π + 80π
→ 112 π cm ^2
Hope this helps you
We have
[tex] \: base \: area \: = \: \pi \: {r}^{2} \: \\ \\ 16\pi = \: \pi \: {r}^{2} \: \: \\ \\ r \: = 4 \: unit \: [/tex]
Now
Surface area = 2πr^2 + 2πrh
→ 2× 16π + 2π × 4× 10
→ 32π + 80π
→ 112 π cm ^2
Hope this helps you